# 手徵性

• 判断载流直导线中的电流方向与感生磁场方向的关系时，让右手大拇指指向电流方向，则其余四指的方向则为磁场方向。
• 判断载流螺线管里的电流方向与螺线管的感生磁场方向关系时，让右手四指由手掌向手指指向电流方向，则大拇指指向感生磁场的北极。

## 手征对称性

### 量子色动力学范例

${\displaystyle {\mathcal {L}}={\overline {u}}\,i\displaystyle {\not }D\,u+{\overline {d}}\,i\displaystyle {\not }D\,d}$

${\displaystyle \psi _{L}={\frac {1-\gamma ^{5}}{2}}\psi }$
${\displaystyle \psi _{R}={\frac {1+\gamma ^{5}}{2}}\psi }$

${\displaystyle {\mathcal {L}}={\overline {u}}_{L}\,i\displaystyle {\not }D\,u_{L}+{\overline {u}}_{R}\,i\displaystyle {\not }D\,u_{R}+{\overline {d}}_{L}\,i\displaystyle {\not }D\,d_{L}+{\overline {d}}_{R}\,i\displaystyle {\not }D\,d_{R}}$

${\displaystyle q=\left({\begin{matrix}u\\d\end{matrix}}\right)}$

${\displaystyle {\mathcal {L}}={\overline {q}}_{L}\,i\displaystyle {\not }D\,q_{L}+{\overline {q}}_{R}\,i\displaystyle {\not }D\,q_{R}}$

U(1)V變換的方式為

${\displaystyle q_{L}\rightarrow e^{i\theta }q_{L}\qquad q_{R}\rightarrow e^{i\theta }q_{R}}$

U(1)A變換的方式為

${\displaystyle q_{L}\rightarrow e^{i\theta }q_{L}\qquad q_{R}\rightarrow e^{-i\theta }q_{R}}$

## 註釋

1. ^ Griffiths, David J., Introduction to Elementary Particles 2nd revised, WILEY-VCH: pp. 338–342, 2008, ISBN 978-3-527-40601-2
2. ^ Koch, Volker. Aspects of Chiral Symmetry. International Journal Modern Physics. 1997, E6: pp. 203–250 [2018-11-06]. （原始内容存档于2015-07-12）.
3. ^ Peskin, Michael; Schroeder, Daniel. An Introduction to Quantum Field Theory. Westview Press. 1995: 670. ISBN 0-201-50397-2.
4. Peskin, Michael; Schroeder, Daniel. An introduction to quantum field theory Reprint. Westview Press. 1995. ISBN 978-0201503975.
5. ^ Povh, Bogdan; Klaus Rith, Christoph Scholz, Frank Zetsche. Particles and Nuclei: An Introduction to the Physical Concepts 6th, illustrated. Springer. 2008: pp.324ff. ISBN 9783540793670.
6. ^ Scadron, M. D.; Zenczykowski, P. Chiral Phase Transitions. Hadronic Journal. 2002, 25: pp. 639–654 [2018-11-06]. （原始内容存档于2018-11-07）.